The PHILCO Phorum

I'm working on this Philco 19 cathedral, and I have a question about C5 which is a Bakelight block part number 4989W according to the parts list on the Philco changes sheet: http://www.philcoradio.com/phorum/attach...?aid=11508

The block in my radio is a 4989AG, but the difference between the two parts seems to be a 300 ohm resistor rather than a 200 ohm resistor. The resistor itself is some looped coated wire in a small paper package. What would be the proper wattage for a replacement? That part is between the cathode of the output tube and the cathode of the IF tube and ground.


http://www.philcoradio.com/images/phorum/19v6.jpg

A 1/2 watt equivalent will do just fine.....

Charlie, I would just reinstall the wire loop, these almost never go bad. You could not put a better resistor in the block. If you want to lower the resistance to 200 ohms, remove about one third of the length. Personally, I would leave it as is.

Steve

If you are speaking of #5, then it dissipates very little.
If your current is say 6mA (I doubt it is) then it is 7mW. Nothing really.