05-13-2010, 06:10 AM
1/2 watt would be fine. Quick math:
Power = current squared times resistance. p/n 17 would be the worst case since it carries load for all three tubes. Figure 10ma for each tube. That's far above the worst case!
So 30ma total, or .03 amps. .03 squared is .0009. Multiply that by 100. Result is .09 watts.
These resistors aren't doing any voltage dropping to speak of. Their main purpose is to provide some isolation between the stages.
GL,
Bill
Power = current squared times resistance. p/n 17 would be the worst case since it carries load for all three tubes. Figure 10ma for each tube. That's far above the worst case!
So 30ma total, or .03 amps. .03 squared is .0009. Multiply that by 100. Result is .09 watts.
These resistors aren't doing any voltage dropping to speak of. Their main purpose is to provide some isolation between the stages.
GL,
Bill
