[morzh]

It is simple.

The resistor connects the target and the plate. Most of the times it sticks out enough to cut it out but it is not necessary as it is open and does nothing bad at all.

the problem (the perceived problem) is that one has to open the socket to replace it and the socket is very brittle (or most of them). And then I had heard also that assembling it back is kinda a b...tch to handle.

So, when I looked at the tube's characteristics, I found out there is very little current, if any, flowing through that resistor. Which means there is also no voltage drop and practically no power dissipation.
So any small resistor will do.

So, what I did was this:

1. I took 1M SMT 0603 size resistor, and I soldered thin (one thread of any multy-thread tinned copper wire) wires to its ends, reliably so they won't break off easily. The length of the wires is roughly 1/2" each.
2. I laid the resistor flat on top of the panel where the tube pins go, and fed the wires to the respective sockets for the tube's pins. I made sure the wires would go there without touching other pins (that is crossing other pins's sockets) and the resistor was also clear of the other pins. It is easy as the 0603 size is 0.06"x0.03" (0.75mm x 1.5mm) and it is very thin (maybe 0.015-0.02").
3. I simply inserted the 6E5 tube back into its panel that would a) keep the resistor pinned and b) keep the wires secured between the pins and the pins' sockets. The wire is thin enough not to impede the tube from being inserted but thick enough so it will get held between the pin and the socket and will provide a good connection.

This is it. It works just fine.
Took me under 10 minutes.