[planigan]

Gary, correct me if I'm wrong but I have been under the belief that we are dealing with a Philco 16. Based on that assumption the block is part number 6287 J (I believe you label it F). Part number 6287 is a double .15uf block. Both caps are in the 1 AF circuit, one in the grid and one in the plate/grid 2d AF. They are not in parallel. Both share the common gnd terminal on the block but go to two different terminals.Some where in this string the value pops up as 1.5uf, at another they are in parallel and total(.15uf in that string part) .3uf. First, if my assumption is right (Mod 16) they are .15uf caps and not in series or parallel. What was being pointed out is that if you can not find a .15uf cap (http://www.justradios.com has .15uf, 630v, metalized poly) you could put two .07uf caps in parallel with each other and get a .14uf cap (in his example three .10uf to get a .3uf). You would not then put those two in parallel with another set because thats not what the block calls for. You would connect each of the two cap assemblies to the gnd term and the the other side of each assemble to there respective terminals (I didn't look up the schematic for the 6387 so I don't know the term #s) such as term 2 and term 5. I ran into this problem on a 37-650, it has two 110pf 1300V in one block, both to gnd and then one to term #2 and the other to term #3. I used two 220pf 500V in series (110pf, 1000V[sorry no 1300V]) as substitutes for each of the 110pfs. I ended up with four caps in that block. I hope this straightens this out because it was becoming very confused. I also hope I didn't add to the confusion. Just as a rule of thumb with two caps of equal uf, when you put the caps in parallel you add the uf, voltage remains the same: when you put them in series you halve the uf and double the voltage. Pat